Question

f(x)=2secx+tanx 0 13 years ago

Answer 1

You mean where 1º derivative is 0?

Answer 2

? I don't understand. I took the derivative and got: f'(x)=2secxtanx+secx2. Then I took out secx: secx(2tanx+secx). And I know I have to set it equal to 0 and solve, I'm having trouble with inside the parentheses though.

Answer 3

write it like this:
\[\frac{1}{cosx}(\frac{2sinx}{cosx}+\frac{1}{cosx})=0\]
now muñtiply bouth sides by cosx to get:
1(2sinx+1)=0
and solve for x

Answer 4

ok?

Answer 5

Okay! thanks!