Question

Find the exact value of the real number y.

y = csc^-1(1)

Answer 1

help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

@RadEn do you get this one??:0

Answer 3

@zepdrix do you know this??

Answer 4

@aaronq
do you have any idea??

Answer 5

@SithsAndGiggles ............wanna help?

Answer 6

please help:(

Answer 7

I see you messaged everyone you know.

Answer 8

haha yes i was desperate :( but no one helped me though....;(

Answer 9

Just type in arccos(1) into wolframalpha.com

Answer 10

It's a pretty good website when it comes to math.

Answer 11

ohhh they said 0 but i need it in a pi form.......@LordVictorius

Answer 12

@LordVictorius

Answer 13

It gives it in that form.

Answer 14

Try it.

Answer 15

\[\large y=arccsc(1) \qquad \rightarrow \qquad \csc(y)=1\]
Recall that \(\large csc(x)=\dfrac{1}{sin(x)}\)

Which gives us,\[\large \frac{1}{\sin(y)}=1 \qquad \rightarrow \qquad \sin(y)=1\]At what angle does the sine function give us a value of 1?

Answer 16

I'm not sure how you came up with zero, did you punch it into Wolfram correctly? :O
http://www.wolframalpha.com/input/?i=y%3Darccsc%281%29

Answer 17

@zepdrix um....pi or 2pi?

Answer 18

Don't you remember your special angles? D: Go back to your unit circle, you must have one lying around somewhere!! c:

Answer 19

Type, "Unit Circle" into google.

Answer 20

@zepdrix ohhhhh pi/2 right?

Answer 21

Yes c: good.

Answer 22

@LordVictorius okay:D

Answer 23

@zepdrix that's the answer?

Answer 24

Yes.

Answer 25

thankyouuuuuu!

Answer 26

np