Question

HELP PLEASE)..Estimate the area of the given function, f(x) = x2 + 1 using 4 inscribed rectangles on the interval [2, 4].

Answer 1

@mathsmind this one first tho

Answer 2

what i understand is that we have to integrate between 2 and 4

Answer 3

i am having some problems it says [Math Processing Error]

Answer 4

\[int_{2}^{4} x^2 dx\]

Answer 5

or is it about drawing estimating the area of the parabula using blocks of squares...

Answer 6

i dont know but this one is too hard :( its worth 7.0 pts im so confused, i feel like crying

Answer 7

\[int_{2}^{4} x^2 dx \]

Answer 8

this work is getting to hard for me

Answer 9

well you have to suffere the pain of knowledge and hardship for a better future, we all went through hard times ...

Answer 10

you should fight back and not let the questions beat you ...

Answer 11

i think this question is saying estimate the area using rectangles, on a proper sheet

Answer 12

so first of all we need to divid the interval

Answer 13

what i mean by that is to divide the interval into 4 sub inscribed intervals

Answer 14

let it be 2, 2.5, 3, 3.5 and 4 because they 2 and 4 are included in the interval using square brackets notation...

Answer 15

okay,i'm working on it

Answer 16

are you with me, this is the logic of the question from my understanding

Answer 17

I am sorry that the equation editor is not functioning propely for me, probably due to browser issue, or technical problem with open study...

Answer 18

A = 0.5[f(2)+f(2.5)+f(3)+f(3.5)+f(4)

Answer 19

i'm looking,i'm here trying to understand

Answer 20

so what is f(2)=?

Answer 21

now before that the reason why i divided the intervals by a step of 0.5 is due to the fact that dx = (4-2)/4=0.5, hence 2, 2.5...etc

Answer 22

let me help you on the first one f(2) = (2)^2+1=4+1=5

Answer 23

what is f(3)=?

Answer 24

what is f(2.5)=?

Answer 25

what is f(3.5)=?

Answer 26

and finally what is f(4)=?

Answer 27

give me a coplue
mins as i work on finish another problem

Answer 28

i don't understand how you got the f(2)= part

Answer 29

ok i will solve it i am replying to 287489327498732987498237 posts at the same time ... hehehe

Answer 30

lol okay, i can't keep hogging you,ill be working on others as i wait.

Answer 31

now young lady, let's see what your problem is...

Answer 32

step one: dx = (4-2)/4 = 1/2=0.5

Answer 33

step two divide the interval [2, 4] into [2, 2.5, 3, 3.5, 4]

Answer 34

step three find : A = 0.5[f(2)+f(2.5)+f(3)+f(3.5)+f(4)]

Answer 35

f(2) =(2)^2+1=5, f(2.5)=(2.5)^2+1= 7.25. f(3)=(3)^2+1=10, f(3.5)=(3.5)^2+1=13.25, and f(4) = (4)^2+1=17

Answer 36

: A = 0.5[5+7.25+10+13.25+17]=? use the calculator

Answer 37

@Ephilo are you there...?

Answer 38

yes im writing it on paper

Answer 39

you need to understand what we did, it is a numerical integration method ....

Answer 40

i understand