Question

lim 1/(x+2)^2
x-> -2 from the left

Answer 1

\[\lim_{x \rightarrow -2-} 1/(x+2)^2 \]

Answer 2

denominator goes to zero through positive numbers (because it is a square) so the limit is \(\infty\)

Answer 3

can you show work

like steps because im confused

Answer 4

i cannot think of any steps to show
the numerator is constantly 1, and the denominator is getting closer and closer to zero

Answer 5

the only possible question is, does it go to \(-\infty\) or \(\infty\) and it is the latter since \((x+2)^2>0\)

Answer 6

how do you know its greater then 0?

Answer 7

because any number squared is positive