The Acculturation Rating Scale for Mexican Americans (ARSMA) is a psychological test developed to measure the degree of Mexican/Spanish versus Anglo/English acculturation of Mexican Americans. The distribution of ARSMA scores in a population used to develop the test was approximately normal, with mean 3.0 and standard deviation 0.8. A further study gave ARSMA to 50 first-generation Mexican Americans. The mean of their scores is x bar = 2.36. If the standard deviation for the first-generation population is also 0.8, give a 95% confidence interval for the mean ARSMA score for first-generation
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OpenStudy (anonymous):
Mexican Americans. The mean of their scores is x bar = 2.36. If the standard deviation for the first-generation population is also 0.8, give a 95% confidence interval for the mean ARSMA score for first-generation Mexican Americans.
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
ok so we know xbar = 2.36, sigma = 0.8, mu = 3 (not used here but we might as well list it) and n = 50
OpenStudy (anonymous):
ok
jimthompson5910 (jim_thompson5910):
s = sigma/sqrt(n)
s = ???
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OpenStudy (anonymous):
s= .8/sqrt50
jimthompson5910 (jim_thompson5910):
keep going
OpenStudy (anonymous):
0.11314?
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
that's s
s = 0.11314
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OpenStudy (anonymous):
ok
jimthompson5910 (jim_thompson5910):
now compute the upper and lower bounds
L = xbar - C*s
U = xbar + C*s
jimthompson5910 (jim_thompson5910):
in this case, C = 1.96 (if you don't remember) because we're working with a 95% CI
jimthompson5910 (jim_thompson5910):
so
xbar = 2.36
C = 1.96
s = 0.11314
OpenStudy (anonymous):
whats c
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jimthompson5910 (jim_thompson5910):
C = 1.96
OpenStudy (anonymous):
L =2.36 - 1.96
U = 2.36 plus 1.96
OpenStudy (anonymous):
?
jimthompson5910 (jim_thompson5910):
good, so
L = ??
U = ??
OpenStudy (anonymous):
l=.4
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OpenStudy (anonymous):
4.32
OpenStudy (anonymous):
LL: 2.36 minus 1.96 = 0.4
UL: 2.36 plus 1.96 = 4.32
jimthompson5910 (jim_thompson5910):
oh wait...not sure why i didn't catch that typo
jimthompson5910 (jim_thompson5910):
my bad
jimthompson5910 (jim_thompson5910):
L = xbar - C*s
U = xbar + C*s
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jimthompson5910 (jim_thompson5910):
L = xbar - C*s
L = 2.36 - 1.96*0.11314
L = ???
OpenStudy (anonymous):
So its LL= 2.1382456
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
U = xbar + C*s
U = 2.36 + 1.96*0.11314
U = ???
OpenStudy (anonymous):
2.5817544
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OpenStudy (anonymous):
--> (2.1382456, 2.5817544) is the answer?
jimthompson5910 (jim_thompson5910):
you got it
jimthompson5910 (jim_thompson5910):
that's all there is to it with confidence intervals
OpenStudy (anonymous):
thanks so much! i have two more proibs, ill repost