Question

You drive your 1100-kg car at a constant speed of 23 mph down a ramp that has a grade of 17 %. Use conservation of energy to find the work done by the frictional force acting from the road on the tires. Then find an expression for the frictional force. Define positive direction in the forward direction. Check the correct answer.(Compare your result with what you found employing Newtons Law.)

Answer 1

is the answer 104,133 N ?

Answer 2

I'll help you out right now, just quickly, to convert from grades to degrees is inverse tangent right? If so...

Answer 3

So now what you do is that you assume that

\[\Sigma F = 0\]

and with that you need to find the component of gravity that is parallel to the slope of the ground the car is sliding on. So... that is...

\[F = - mgsin \Theta \]

Now finally, you get

\[\Sigma F = F_f -mgsin \Theta = 0\]

So when you solve for \[F_f\] or the frictional force. It is negative (opposite dirction of motion) and solved correctly.

\[F_f = -1,808.5N\]

Answer 4

thank youuu