What proportion of all Americans believe the president is doing a good job? A recent poll found that 39% of 1000 randomly selected Americans approved of the way George W. Bush is handling his job as president.
a) Does this mean that only 39% of all Americans approve of the way George W. Bush is handling his job as president?
b) For a sample proportion, as long as the population is greater than ten times the sample size, we can approximate the standard deviation to be the square root of p times 1 minus p divided by n What is the standard deviation for this sample?
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OpenStudy (anonymous):
c) What is the critical value for a 90% confidence interval?
d) What is the critical value for a 95% confidence interval?
e) What is the 90% confidence interval? Be sure to include the formula with your numbers plugged in. Use the model: p plus or minus z times the square root of p times 1 minus p divided by n
f) What is the 95% confidence interval?
OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (comm.dan):
A @schmidtdancer
OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (comm.dan):
What do you think it is? @schmidtdancer
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OpenStudy (anonymous):
im not sure.
OpenStudy (anonymous):
@jim_thompson5910 ? how do i start with a
OpenStudy (comm.dan):
Ok
jimthompson5910 (jim_thompson5910):
you have a SRS of 1000 people
There are about 300 million people in this country. Even if you exclude young children who can't vote, that's still a lot of people.
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
I got no, this 39 percent refers to the 1000 Americans sampled.
jimthompson5910 (jim_thompson5910):
so do you think a SRS of 1000 people could represent a population of 300 million accurately?
OpenStudy (anonymous):
what about b? i got:(b) sqrt np(1-p)
= sqrt(1000(0.39)0.61)
= 237.9 <----
OpenStudy (anonymous):
?
jimthompson5910 (jim_thompson5910):
use sqrt(p(1-p)/n)
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OpenStudy (anonymous):
so is that b?
jimthompson5910 (jim_thompson5910):
that's part of b, yes
OpenStudy (anonymous):
is b the answer i had..?
OpenStudy (anonymous):
237.9
OpenStudy (anonymous):
is c: (0.3646 , 0.4154)
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jimthompson5910 (jim_thompson5910):
s = sqrt(p(1-p)/n)
s = sqrt(0.39(1-0.39)/1000)
s = ???
OpenStudy (anonymous):
s=0.01542400726
jimthompson5910 (jim_thompson5910):
better
OpenStudy (anonymous):
so b is: s = sqrt(0.39(1-0.39)/1000)
s= 0.01542400726
OpenStudy (anonymous):
whats c? i got (0.3646 , 0.4154)
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OpenStudy (anonymous):
is b and c right^^
jimthompson5910 (jim_thompson5910):
yes b is s = sqrt(0.39(1-0.39)/1000)
s= 0.01542400726
OpenStudy (anonymous):
ok!
OpenStudy (anonymous):
c?
jimthompson5910 (jim_thompson5910):
c) and d) are found using that wolfram alpha calculator we used before
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OpenStudy (anonymous):
ok is what i have right tho
jimthompson5910 (jim_thompson5910):
remember how we got 1.645 and 1.96 ?
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
?
jimthompson5910 (jim_thompson5910):
well those are the critical values for the 90% and the 95% confidence intervals
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
how do i find c with it
jimthompson5910 (jim_thompson5910):
just something you'll have to look up in a table or use a calc (or memorize)
jimthompson5910 (jim_thompson5910):
those are the answers to C and D because that's all those parts want
OpenStudy (anonymous):
Oh ok. so c is 1.645
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OpenStudy (anonymous):
d is 1.96?
OpenStudy (anonymous):
(e) (0.3646,0.4154)
(f) (0.3598 , 0.4202) are these right
jimthompson5910 (jim_thompson5910):
yep you got c and d correct
jimthompson5910 (jim_thompson5910):
hold on while i check e and f
OpenStudy (anonymous):
kk
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