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Mathematics 22 Online
OpenStudy (anonymous):

help please

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

Directrix (directrix):

The theorem I think we need is this one: Theorem: If an altitude is drawn to the hypotenuse of a right triangle, either leg of the triangle is the geometric mean between the length of the hypotenuse and the segment of the hypotenuse adjacent to that leg.

OpenStudy (anonymous):

go on

Directrix (directrix):

Go ahead. I was just writing up a drawing for this problem.

Directrix (directrix):

Directrix (directrix):

@sharon_penn I'm waiting for you to say something about solving the equations on the attachment.

Directrix (directrix):

I know how to do this and will help if you will just tell me what your thinking is on the problem.

OpenStudy (anonymous):

My thought was that the sides would equal so I thought that the answer x=2sqrt3 y=4 was correct

OpenStudy (anonymous):

am i right?

Directrix (directrix):

I'll work the equation here. y/12 = 28/y y = 4*sqrt(21)

OpenStudy (anonymous):

awesome

Directrix (directrix):

16/x = x/28 x = 8*sqrt(7)

Directrix (directrix):

Is that what you got?

OpenStudy (anonymous):

no but I see how you got it :)

Directrix (directrix):

Okay. Learn those Geometry theorems. :)

OpenStudy (anonymous):

ty

Directrix (directrix):

Glad to help.

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