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OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
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OpenStudy (anonymous):
Directrix (directrix):
The theorem I think we need is this one:
Theorem: If an altitude is drawn to the hypotenuse of a right triangle, either leg of the triangle is the geometric mean between the length of the hypotenuse and the segment of the hypotenuse adjacent to that leg.
OpenStudy (anonymous):
go on
Directrix (directrix):
Go ahead. I was just writing up a drawing for this problem.
Directrix (directrix):
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Directrix (directrix):
@sharon_penn
I'm waiting for you to say something about solving the equations on the attachment.
Directrix (directrix):
I know how to do this and will help if you will just tell me what your thinking is on the problem.
OpenStudy (anonymous):
My thought was that the sides would equal so I thought that the answer x=2sqrt3 y=4 was correct
OpenStudy (anonymous):
am i right?
Directrix (directrix):
I'll work the equation here.
y/12 = 28/y
y = 4*sqrt(21)
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OpenStudy (anonymous):
awesome
Directrix (directrix):
16/x = x/28
x = 8*sqrt(7)
Directrix (directrix):
Is that what you got?
OpenStudy (anonymous):
no but I see how you got it :)
Directrix (directrix):
Okay. Learn those Geometry theorems. :)
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