Question

Anyone know what i am doing wrong here?
Im trying to find the base and the area of pyramid but i get a 1e0.02 something like this answer help!!

Answer 1

#include <iostream>
#include <iomanip>
using namespace std;

int main()
{

float length, area, base, VP, height ;
cout << "The volume of the square base pyramid." << endl;

cout << "Enter the length of the pyramid's base :" << endl;
cin >> length ;

cout << "Enter the height of the pryamid :" << endl;
cin >> height ;

area = length*length ;

VP = area*height ;

cout <<setprecision (2) << "The area of the base is : " << area << endl;;

cout <<setprecision(2) << "The height of the pyramid is : " << height<< endl ;

cout << setprecision (2) <<"The volume of the pyramid is : " << VP << endl;

Answer 2

Are you getting that for the base or the area? aka, are you getting the base to come out correctly?

Answer 3

no that is the problem... when i input for length 10.0 and height 5.0
i get an area of something like 1e002 or something and for volume i get 2e002 or something like that

Answer 4

for debugging purposes (and to teach) try putting cout << area right after the area calculation and run that. If you're still getting the wrong answer, you know your error is in the top half of your code, otherwise the second half. Make sense?

Answer 5

Please post what you get once you run that. I'd like to see what you get.

Answer 6

The volume of the square base pyramid.
Enter the length of the pyramid's base :
10.0
Enter the height of the pryamid :
5.0
The area of the base is : 1e+002
The height of the pyramid is : 5
The volume of the pyramid is : 1.7e+002
Press any key to continue . . .

this is what i got on my c-command prompt... =(

Answer 7

#include <iostream>
#include <iomanip>
using namespace std;

int main()
{

float length, area , base, height, VP ;



cout << "The volume of the square base pyramid." << endl;

cout << "Enter the length of the pyramid's base :" << endl;
cin >> length ;

cout << "Enter the height of the pryamid :" << endl;
cin >> height ;



VP = (area*height)/3 ;
area = length*length ;

cout <<setprecision (2) << "The area of the base is : " << area << endl;;

cout <<setprecision(2) << "The height of the pyramid is : " << height<< endl ;

cout << setprecision (2) <<"The volume of the pyramid is : " << VP << endl;

Answer 8

After area = length*length put in a line that says cout << area; for me please and post the output once again

Answer 9

#include <string>
#include <iomanip>
using namespace std;

int main()
{

float length, area, base, height, VP ;



cout << "The volume of the square base pyramid." << endl;

cout << "Enter the length of the pyramid's base :" << endl;
cin >> length ;

cout << "Enter the height of the pryamid :" << endl;
cin >> height ;



VP = (area * height) / 3 ;

area = sqrt(length) ;

cout << area << endl;

cout <<setprecision (2) << "The area of the base is : " << area << endl;;

cout <<setprecision(2) << "The height of the pyramid is : " << height<< endl ;

cout << setprecision (2) <<"The volume of the pyramid is : " << VP << endl;

Answer 10

i got an error.

Answer 11

what's the error say?

Answer 12

i think im doing the area wrong.... how do i multiply itself twice?

Answer 13

area = length * length;

Answer 14

also, you should use double instead of float.

Answer 15

that area = length * length doesnt work
when i do that the answer becomes 1e+002 or something

Answer 16

your order is wrong. Area should be calculated first. otherwise it will calculate based on a pointer to garbage. (your variable) switch the area=length*length to be before your Vp = line

Answer 17

i dont think that matters.

#include <iostream>
#include <string>
#include <iomanip>
using namespace std;

int main()
{

float length, base, height, VP ;
double area ;


cout << "The volume of the square base pyramid." << endl;

cout << "Enter the length of the pyramid's base :" << endl;
cin >> length ;

cout << "Enter the height of the pryamid :" << endl;
cin >> height ;





area = length * length ;

VP = (area * height) / 3 ;

cout <<setprecision (2) << "The area of the base is : " << area << endl;;

cout <<setprecision(2) << "The height of the pyramid is : " << height<< endl ;




cout << setprecision (2) <<"The volume of the pyramid is : " << VP << endl;

Answer 18

still get same 1e+002

Answer 19

ok, I copied your code and tried it in my system. I also included stdio.h in my header. you might try that as well

Answer 20

Did it work?

Answer 21

i dont think i am able to use that because i did not learn that in my class.

Answer 22

just ran this without stdio and it works just fine. attached is the code

Answer 23

did that work for you?

Answer 24

let me check

Answer 25

did not work =(

Answer 26

I just compiled and ran @charpede's temp.cpp and it seems to work fine:


The volume of the square base pyramid.
Enter the length of the pyramid's base :
3
Enter the height of the pryamid :
5
The area of the base is : 9
The height of the pyramid is : 5
The volume of the pyramid is : 15


Can you paste your full output?

Answer 27

ok
#include <iostream>
#include <iomanip>

using namespace std;

int main()
{
float length, area , base, height, VP ;
cout << "The volume of the square base pyramid." << endl;
cout << "Enter the length of the pyramid's base :" << endl;
cin >> length ;
cout << "Enter the height of the pryamid :" << endl;
cin >> height ;

area = length*length ;
VP = (area*height)/3 ;
cout <<setprecision(2) << "The area of the base is : " << area << endl;;
cout <<setprecision(2) << "The height of the pyramid is : " << height<< endl;
cout << setprecision(2) <<"The volume of the pyramid is : " << VP << endl;

return 0 ;
}

Answer 28

The reason you're getting results that look something like `1.4e+02` sometimes is that it's outputting in scientific notation. This is because you're limiting the precision to 2 significant digits and you're inputting values that result in answers what are normally written as more than two digits in decimal form. `1.4e+02 = 140`

If you want to output the answers up to two `decimal places`, just add `cout.setf(ios_base::fixed);` before you output.

Answer 29

i dont know what that is i think im suppose to use the basic stuff we learned. i have no idea what that you wrote is though..

Answer 30

What I was saying is: To get rid of your problem, either don't use `setprecision()`, or do this:

#include <iostream>
#include <iomanip>
using namespace std;
int main() {
float length, area , base, height, VP ;
cout << "The volume of the square base pyramid." << endl;
cout << "Enter the length of the pyramid's base :" << endl;
cin >> length ;
cout << "Enter the height of the pryamid :" << endl;
cin >> height ;
area = length*length ;
VP = (area*height)/3 ;

cout.setf(ios_base::fixed);
cout <<setprecision(2) << "The area of the base is : " << area << endl;
cout <<setprecision(2) << "The height of the pyramid is : " << height<< endl;
cout << setprecision(2) <<"The volume of the pyramid is : " << VP << endl;
return 0 ;
}