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OpenStudy (anonymous):
Please Help... Differentiate... Y= Srqt(1+ 2e^3x)
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OpenStudy (anonymous):
\[Y= \sqrt{1+2e^3x}\]
OpenStudy (anonymous):
chain rule plus product rule \[\frac{d}{dx}\sqrt{f(x)}=\frac{f'(x)}{2\sqrt{f(x)}}\] with \[f(x)=1+2e^{3x}, f'(x)=6e^{3x}\]
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