f you were to use the substitution method to solve the following system, choose the new system of equations that would result if x was isolated in the second equation. 3x + y + 2z = 1 x + 2y - z = -8 3x - y - 3z = 18
@terenzreignz
@terenzreignz
So, in the second equation, as instructed, isolate x IE rearrange it so that x stands alone in one side of the equation.
a. 7y - z = 25 5y - 6z = 42 b. -5x - 5z = -10 6x - z = 19 c. 7x + 3z = -10 0x - 5z = 19 d. -5y + 5z = 25 -7y = 42
x=-8-2y+z
\[x=-8-2y+z\]
@Turner
That's right. Now replace the x in both the first and third equations by this new expression.
alright one sec
\[3(-8-2y+2)+2z=1\]
\[3(-8-2y+z)-y-3z=18\]
the 2 should be a z in the ( )
So, simplify this. Do the same with the third equation.
ok one sec
-24-6y+5z=1
-24-5y+z=18
is that correct
Check if you're using the correct equation! 3x + y + 2z = 1 Now, do it again, replace the x.
ok
x = z - 2y - 8
so it should look like this -24-6y+3z+y+2z=1
-24-7y+5z=1
-6y + y = 7y? recheck.
-24-5y+5z=1
Yes. But bring that -24 over to the other side.
-5y+5z=25
I guess at this point we can stop. Only one of the choices has this equation. You can verify that doing the same substitution to the third equation will add up.
ok i have one more
If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the first and second equations, then the second and third equations. x + y - 3z = -8 2x + 2y + z = 12 3x + y - z = -2
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