Question

The kinetic energy acquired by a mass m in traveling distance d,starting from rest,under the action of a constant force is directly propotional to?
A)m
B)m^0
C)m^1/2
D)m^-1/2

Answer 1

really!? work done = change in kinetic energy! :-/

Answer 2

Mashy, despite of how mean that answer was, it is correct.

Answer 3

he is my bro.. so don't worry :D

Answer 4

Lmao okay

Answer 5

and he is appearing for IIT :D.. what a joke :D

Answer 6

-.-
sorry it was my net yesterday..couldnt post options..
A)m
B)m^0
C)m^1/2
D)m^-1/2

Answer 7

I thought of it like this..
constant force
so acceleration = 0
v=constant
so directly propotional to m?
but its wrong..

Answer 8

@experimentX,,okay something serious

Answer 9

work done...

Answer 10

options are
A)m
B)m^0
C)m^1/2
D)m^-1/2

Answer 11

I got A but its wrong

Answer 12

most likely B ...

Answer 13

y?

Answer 14

there is constant force, ... and the 'd' is fixed, not matter what your mass is ... it will acquire the same KE.

Answer 15

numerically it should be m but?

Answer 16

you are applying same force to all ... along the same distance, ... it doesn't matter if your object is sum or an atom, the work done must be same ... which is equal to it's KE

Answer 17

const force, so accn 0 ,, wow! :O

Answer 18

so you want a numerical answer right?
distance travelled=d=v^2/2a where a-->acceleration
by manipulating s=K/F . so distance traveled is independent of mass.
and if you think K=1/2mv^2, here v is not constant, so you cannot use this.

Answer 19

NO

Answer 20

oops

Answer 21

http://i0.kym-cdn.com/entries/icons/original/000/007/423/untitle.JPG

Answer 22

I think constant force will produce constant acceleration.

Answer 23

if force is constant then how will there be difference in acceleration o.O

Answer 24

yes const.acc

Answer 25

akkcho ?
http://profile.ak.fbcdn.net/hprofile-ak-prn1/s160x160/12202_445245428869402_1865563081_a.jpg

Answer 26

imagine a falling object ... the force is always constant, for small distance.

Answer 27

that happens in SHM ! :O

Answer 28

\[F = -kx\]

Answer 29

omg

work done = change in kinetic energy
work done = Fd
F= ma
hence work done = mad (lol)
since initial k.E = 0.. change in K.E = Final K.E - 0 = Final K.E
hence Final K.E = mad
or Final k.E directly proportional to m !!

Answer 30

i think i said the same?
but its B) and I got it too..
also you did it wrong

Answer 31

the kinetic energy acquired IS proportional to mass.. think logically

your force is constant.. the distance for which you are putting the force is ALSO constant

so imagine throwing a BIGGGG boulder.. and imagine throwing a small rock!!

in both case.. the force you put on them is fairly same? .. cause it depends on your strength?

and your swing action is more or less the same?? hence the distance is the saem??
now you are saying both the boulder and the small rock gain the same speed K.E?

Answer 32

WAIT WAIT WAIT...i got i got it! :D

Answer 33

the force is constant, independent of the mass! -_-

Answer 34

they get same K.E... but not same speed!!

Answer 35

in this ques.

Answer 36

yes yes.. correct.. !! :P
independent of mass!!

Answer 37

i get it.. i get it..!! hope DLS gets it too!?

Answer 38

Its not possible that DLS doesn't get it! ^_^
He's a champ! \m/

Answer 39

\[\LARGE WD=FORCE \times DISPLACEMENT\]
force=constant
displacement=constant
WD=constant

Answer 40

wow shubh.. that was INTENSE sarcasm.. of a very high level :D

Answer 41

..

Answer 42

DLS (Dynamic light scattering (also known as photon correlation spectroscopy or quasi-elastic light scattering))

Answer 43

now he is just braggin :P

Answer 44

That wasn't sarcasm! ^_^

Answer 45

i got confused again

Answer 46

why confused? just like you said.. work done is constant.. hence k.e is also constant!

Answer 47

i mean in the other question :/

Answer 48

So what's the net result..I am literally confused

Answer 49

the result is that.. K.E is independent of Mass in this case

Answer 50

How does this fits in , in a real life scenario?

Answer 51

it does fit in.. the real life example i gave.. it works for that too!