Question

prime question. f(x)=sqrt(4x)
f`(x)=

Answer 1

f(x) = sqrt(4x)
f'(x) = 1/2 (1/sqrt(4x)) * d/dx (4x)
f'(x) = 1/2 (1/sqrt(4x)) * (4)

Answer 2

so, 4x^1/2?

Answer 3

I dont understand the way you write.

Answer 4

do you know chain rule??

Answer 5

yes, but im not sure how do i solve prime when sqrtroot is invloved

Answer 6

I thought the answer is 2/x^-(1/2)?

Answer 7

derivative of x^0.5 is 0.5 (x^(0.5-1) = 0.5 (x^(-0.5)) = 0.5 ( 1/x^(0.5))

Answer 8

mmmm...

Answer 9

so its 2/x^-(0.5)?

Answer 10

what the final answer??

Answer 11

2/x^-(0.5)?

Answer 12

2/ sqrt(4x)
4x not x
in your form of answer 2/(4x)^-(0.5)

Answer 13

Ahhh :( why im getting the wrong answer :/

Answer 14

I entered the answer and it was wrong

Answer 15

well i suggest that you use the equation generator to give the question because otherwise there can be misunderstanding.

Answer 16

as i get it it should be
\[\frac{ 2 }{ \sqrt{4x} } = \frac{ 1 }{ \sqrt{x} }\]

Answer 17

Thank you for helping me

Answer 18

:)