How do I find the point of discontinuity for 6-3x/x^2-5x+6=y? Please explain all steps.

Question

harsimran_hs4 · Answer

just find the values of x for which only denominator is zero
thats it

anonymous · Answer

But how do I get zero in the denominator? I need it spelled out for me because I'm not very good with math...

harsimran_hs4 · Answer

well as i get it x^2-5x+6 is the denominator 
so tell me the values of x for which x^2-5x+6 = 0
can u?

anonymous · Answer

But aren't those numbers the domain...?

harsimran_hs4 · Answer

well if take out all the points where the function is defined what we call domain
then you will not find any point in the domain where this function is discontinuous(taking of only polynomial functions)
so we consider the real number line and the points where denominator is zero is the answer

anonymous · Answer

So because there are domains there is no point of discontinuity...?

harsimran_hs4 · Answer

yes if you talk of find all the points of discontinuity in the domain of the function 
then you won`t find any and there is no point asking this question

whereas in your question there is no mention of domain so we have to find points of discontinuity over the real numbers and for finding those numbers find those values where denominator is zero

anonymous · Answer

Oh, thank you ^.^