Question

Create your own binomial expression with a radical in the second term.

Part 1: Identify the conjugate and explain, in complete sentances, why it is the conjugate. (1 point)

Part 2: Multiply your original binomial expression and its conjugate. What happened to the radicals and why? (1 point)

Last one for right now, peopleee <3 please!

Answer 1

So now, how do i solve it in reguards to my directions?

Answer 2

To identify the conjugate acid, look for the pair of compounds that are related

Answer 3

I really just need the answer in step form. like step 1: asdfjak;dlfj Step 2: ajkfak;dfg

Answer 4

1+√5

Answer 5

This is with the sign changed though 1 - √5

Answer 6

(1-√5)(1+√5) = 6

Answer 7

The conjugate has the same rational part (the 5 in this example) and the opposite sign on the radical part (sqrt(3) in this example).
The conjugate is 5 - sqrt(3)

Answer 8

2. The radicals disappear because you're using the difference of two squares: (a-b)(a+b) = a^2-b^2 and a radical squared is rational

Answer 9

omg thank you <3