Question

how do i completely factor this??
x^2-16x+55

Answer 1

Forget about the = 0 for now.

(x-11)(x-5) is factored. If you want to solve:

(x-11)(x-5)=0

Set each equal to 0.

x-11=0 x-5=0
x=11 x=5

So x=5,11

Answer 2

thanks

Answer 3

np

Answer 4

would you be abel to help me on my other math homework and help me show my work bc if i dont my teacher will yell at me

Answer 5

suree

Answer 6

now i got to factor trinomials
6x^2+17x+12

Answer 7

There are a few ways to do this, but the easiest way I know of to factor a trinomial in the form ax^2 + bx + c is the following:
1. Multiply a and c.
2. If the sign of c is positive, select a pair of factors for the product ac that will have a sum of b. If the sign of c is negative, select a pair of factors for ac that will have a difference of b.
3. Replace the term bx with either the sum or difference.
4. Group and factor.

In this problem, 6*12 = 72. Since it is positive 12, we need a pair of factors of 72 that has a sum of -17. This pair of factors is -8 and -9.

So we rewrite the original expression as 6x^2 - 9x - 8x + 12.

Then, separate this expression into two groups of two terms using parentheses.

(6x^2 - 9x) + (-8x + 12)

Within each pair of parentheses, factor out any common factor.

3x(2x - 3) + -4(2x - 3)

Notice that both parenthetical expressions are the same. Factor out this common parenthetical expression.

The result is (2x - 3) (3x - 4)

Answer 8

doing the same 6y^2+7y-24

Answer 9

6y² + 7y - 24 = 0
y² + 7/12y = 4 + (7/12)²
y² + 7/12y = 576/144 + 49/144
(y + 7/12)² = 625/144
y + 7/12 = +/- 25/12

Factors:
= y + 7/12 - 25/12, = y - 18/12, = y - 3/2, = 2y - 3
= y + 7/12 + 25/12, = y + 32/12, = y + 8/3, = 3y + 8

Answer: (2y - 3)(3y + 8)

Checking:
= (2y - 3)(3y + 8)
= 6y² + 16y - 9y - 24
= 6y² + 7y - 2

Answer 10

can we do three more plzz bcnow i think i know how to do it

Answer 11

16r^2-16r-12

Answer 12

4x^2-20x+25

Answer 13

4x^2+7x+3

Answer 14

hold on

Answer 15

@jim_thompson5910

Answer 16

whats that for

Answer 17

16r^2-16r-12


4(4r^2-4r-3) ... factor out the GCF 4


4(4r^2+2r-6r-3) ... break up -4r into 2r - 6r (see note below)


4((4r^2+2r)+(-6r-3))


4(2r(2r+1)+(-6r-3))


4(2r(2r+1)-3(2r+1))


4(2r-3)(2r+1)



---------------------------------------------------------------------------


16r^2-16r-12


completely factors to


4(2r-3)(2r+1)

Answer 18

Note: the numbers 2 and -6 both add to -4 AND multiply to -12

Answer 19

so that explains why I rewrote

4r^2-4r-3

into

4r^2+2r-6r-3

Answer 20

let me know if anything doesn't make any sense

Answer 21

it is

Answer 22

so it all makes sense?