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Physics 22 Online
OpenStudy (anonymous):

What are the coefficients used to balance the following equation, AlCl3 + Ca --> CaCl2 + Al.

OpenStudy (anonymous):

(2/3)AlCl3 + Ca --> CaCl2 + (2/3)Al

OpenStudy (anonymous):

you can multiply by 3 throughout if you prefer integers

OpenStudy (anonymous):

both are correct though

OpenStudy (anonymous):

Well... In Hess' Law, fractional coefficients are ok because you are calculating enthalpy, ΔH . In reality, we can't get fractional amounts of molecules, only fractional moles :P P.S. This goes in Chemistry!! >.<

OpenStudy (anonymous):

not really

OpenStudy (anonymous):

you are forgetting that we are using mole ratios in the equations. 1 mole is just the avogadro's constant

OpenStudy (anonymous):

so you wont get fractional molecules or what not, most of the time.

OpenStudy (anonymous):

this is confusing so the coeficients are 2/3 and 2/3 ?

OpenStudy (anonymous):

{i need to stop second-guessing myself} Well, you can use 2, 3, 3, 2 if you prefer (and I still insist it would be best)

OpenStudy (anonymous):

because i got 2332 and got it wrong haha

OpenStudy (anonymous):

oh wait

OpenStudy (anonymous):

i multiplied wrongly

OpenStudy (anonymous):

i mean 2323 sorry thats why i put and got it wrong

OpenStudy (anonymous):

2 3 3 2... again i multiplied wrongly....

OpenStudy (anonymous):

(2/3)AlCl3 + Ca --> CaCl2 + (2/3)Al multiply all by 3 if you prefer integers. you will get 2AlCl3 + 3Ca --> 3CaCl2 + 2Al

OpenStudy (anonymous):

sorry for the confusion. Using (2/3) as coeeficients are correct. But multiplying them to get integers are what I would call aesthetics

OpenStudy (anonymous):

so the answer is 2332 those are the coeficients

OpenStudy (anonymous):

As to how i got 2/3 as the coeeficients, first i balance the number of Cl. reactant has 3 while product has 2 using maths, to make the 3 into 2, i multiply 3 by 3/2

OpenStudy (anonymous):

multiply 3 by 2 / 3 i mean

OpenStudy (anonymous):

that would mean i have 2/3 moles of Al in reactants. Product has 1. So, multiply Al in product by 2/3 and it is balanced

OpenStudy (anonymous):

thanks it was correct thank you guys for ur help :D

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