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Mathematics 23 Online
OpenStudy (anonymous):

help, see attachment

OpenStudy (anonymous):

OpenStudy (anonymous):

you use a table like this one http://www.icess.ucsb.edu/gem/material_clima_I/normal01.jpg

OpenStudy (anonymous):

still dont understand

OpenStudy (anonymous):

P(Z>b) is the area to the left of b, P(Z<b) is the area to the right of b

OpenStudy (anonymous):

what about P(Z>b) = 0.0735?

OpenStudy (anonymous):

i have those backwards

OpenStudy (anonymous):

P(Z>b) is the area to the right of b, P(Z<b) is the area to the left of b

OpenStudy (anonymous):

P(b less Z less 0.55) = 0.2487?

OpenStudy (anonymous):

P(Z>b) = 1 - P(Z<b) so find P(Z<b)=1-.0735

OpenStudy (anonymous):

look on the chart for the b which gives .9265

OpenStudy (anonymous):

but there is no .9265

OpenStudy (anonymous):

it's there

OpenStudy (anonymous):

the answer is 1.45

OpenStudy (anonymous):

why don't we just look at it directly

OpenStudy (anonymous):

i got - 1.45

OpenStudy (anonymous):

?

OpenStudy (anonymous):

for part b?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

it should be +1.45

OpenStudy (anonymous):

what about part c?

OpenStudy (anonymous):

break it up into 2 parts

OpenStudy (anonymous):

P(b<Z<.55)=P(Z<.55)-P(Z<b)

OpenStudy (anonymous):

P(Z<.55) = .7088

OpenStudy (anonymous):

so P(Z<b) = .7088-.2487

OpenStudy (anonymous):

P(Z<b) = .4601

OpenStudy (anonymous):

ok, what about the part 4

OpenStudy (anonymous):

P(-b < Z < b) = 2 * P(.5 < Z < b)

OpenStudy (anonymous):

P(.5 < Z < b) = .7415 / 2 = .3708

OpenStudy (anonymous):

which one is correct, are you doing part c?

OpenStudy (anonymous):

which is equivilent to finding P(Z < b ) = .8708

OpenStudy (anonymous):

which one is correct, are you doing part c?

OpenStudy (anonymous):

from the table, b = 1.13

OpenStudy (anonymous):

part d

OpenStudy (anonymous):

what about part c?

OpenStudy (anonymous):

part we had P(Z<b) = .4601

OpenStudy (anonymous):

part c

OpenStudy (anonymous):

find P(Z<b) = (.5 - .4601) + .5, then flip the sign

OpenStudy (anonymous):

P(Z < b) = .5399, b = 1.0 so the answer to part c is -1.0

OpenStudy (anonymous):

so cunfused now

OpenStudy (anonymous):

wait

OpenStudy (anonymous):

it's -0.1, read the chart wrong

OpenStudy (anonymous):

you need to learn how to use the chart XD

OpenStudy (anonymous):

for the part d , where did you get that .5?

OpenStudy (anonymous):

because the chart is symmetric you just find the right half and multiply by 2

OpenStudy (anonymous):

so the answer is 1.13

OpenStudy (anonymous):

?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

thank you very much

OpenStudy (anonymous):

can you explain one more question?

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

OpenStudy (anonymous):

that's very similar

OpenStudy (anonymous):

convert the grades to zscore with (grade - mean)/stddev then use the table to find probabilities

OpenStudy (anonymous):

can you take first one as an example?

OpenStudy (anonymous):

z = (55.5-67)/7 = -1.643 Find P(Z < -1.643)

OpenStudy (anonymous):

but there is no -1.643?

OpenStudy (anonymous):

the chart only gives half the values because it's symmetric

OpenStudy (anonymous):

P(Z < -1.643) = P(Z > 1.643)

OpenStudy (anonymous):

P(Z > 1.643) = 1 - P(Z < 1.643)

OpenStudy (anonymous):

what is P(Z < 1.643) from the table ?

OpenStudy (anonymous):

about .95

OpenStudy (anonymous):

so the answer is 1-.95 = .05

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

for the second one i got 0.6443

OpenStudy (anonymous):

that is P(Z < .37) you need P(Z > .37)

OpenStudy (anonymous):

0.7357?

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

P(Z < b) + P(Z > b) = 1

OpenStudy (anonymous):

1-0.37?

OpenStudy (anonymous):

1-.6443

OpenStudy (anonymous):

0.3357

OpenStudy (anonymous):

that's it

OpenStudy (anonymous):

third one

OpenStudy (anonymous):

how to find that one?

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