Mathematics
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OpenStudy (anonymous):
help, see attachment
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OpenStudy (anonymous):
OpenStudy (anonymous):
still dont understand
OpenStudy (anonymous):
P(Z>b) is the area to the left of b, P(Z<b) is the area to the right of b
OpenStudy (anonymous):
what about P(Z>b) = 0.0735?
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OpenStudy (anonymous):
i have those backwards
OpenStudy (anonymous):
P(Z>b) is the area to the right of b, P(Z<b) is the area to the left of b
OpenStudy (anonymous):
P(b less Z less 0.55) = 0.2487?
OpenStudy (anonymous):
P(Z>b) = 1 - P(Z<b) so find P(Z<b)=1-.0735
OpenStudy (anonymous):
look on the chart for the b which gives .9265
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OpenStudy (anonymous):
but there is no .9265
OpenStudy (anonymous):
it's there
OpenStudy (anonymous):
the answer is 1.45
OpenStudy (anonymous):
why don't we just look at it directly
OpenStudy (anonymous):
i got - 1.45
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OpenStudy (anonymous):
?
OpenStudy (anonymous):
for part b?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
it should be +1.45
OpenStudy (anonymous):
what about part c?
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OpenStudy (anonymous):
break it up into 2 parts
OpenStudy (anonymous):
P(b<Z<.55)=P(Z<.55)-P(Z<b)
OpenStudy (anonymous):
P(Z<.55) = .7088
OpenStudy (anonymous):
so P(Z<b) = .7088-.2487
OpenStudy (anonymous):
P(Z<b) = .4601
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OpenStudy (anonymous):
ok, what about the part 4
OpenStudy (anonymous):
P(-b < Z < b) = 2 * P(.5 < Z < b)
OpenStudy (anonymous):
P(.5 < Z < b) = .7415 / 2 = .3708
OpenStudy (anonymous):
which one is correct, are you doing part c?
OpenStudy (anonymous):
which is equivilent to finding P(Z < b ) = .8708
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OpenStudy (anonymous):
which one is correct, are you doing part c?
OpenStudy (anonymous):
from the table, b = 1.13
OpenStudy (anonymous):
part d
OpenStudy (anonymous):
what about part c?
OpenStudy (anonymous):
part we had P(Z<b) = .4601
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OpenStudy (anonymous):
part c
OpenStudy (anonymous):
find P(Z<b) = (.5 - .4601) + .5, then flip the sign
OpenStudy (anonymous):
P(Z < b) = .5399, b = 1.0
so the answer to part c is -1.0
OpenStudy (anonymous):
so cunfused now
OpenStudy (anonymous):
wait
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OpenStudy (anonymous):
it's -0.1, read the chart wrong
OpenStudy (anonymous):
you need to learn how to use the chart XD
OpenStudy (anonymous):
for the part d , where did you get that .5?
OpenStudy (anonymous):
because the chart is symmetric you just find the right half and multiply by 2
OpenStudy (anonymous):
so the answer is 1.13
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OpenStudy (anonymous):
?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
thank you very much
OpenStudy (anonymous):
can you explain one more question?
OpenStudy (anonymous):
sure
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OpenStudy (anonymous):
OpenStudy (anonymous):
that's very similar
OpenStudy (anonymous):
convert the grades to zscore with (grade - mean)/stddev then use the table to find probabilities
OpenStudy (anonymous):
can you take first one as an example?
OpenStudy (anonymous):
z = (55.5-67)/7 = -1.643
Find P(Z < -1.643)
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OpenStudy (anonymous):
but there is no -1.643?
OpenStudy (anonymous):
the chart only gives half the values because it's symmetric
OpenStudy (anonymous):
P(Z < -1.643) = P(Z > 1.643)
OpenStudy (anonymous):
P(Z > 1.643) = 1 - P(Z < 1.643)
OpenStudy (anonymous):
what is P(Z < 1.643) from the table ?
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OpenStudy (anonymous):
about .95
OpenStudy (anonymous):
so the answer is 1-.95 = .05
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
for the second one i got 0.6443
OpenStudy (anonymous):
that is P(Z < .37) you need P(Z > .37)
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OpenStudy (anonymous):
0.7357?
OpenStudy (anonymous):
nope
OpenStudy (anonymous):
P(Z < b) + P(Z > b) = 1
OpenStudy (anonymous):
1-0.37?
OpenStudy (anonymous):
1-.6443
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OpenStudy (anonymous):
0.3357
OpenStudy (anonymous):
that's it
OpenStudy (anonymous):
third one
OpenStudy (anonymous):
how to find that one?