2^(2x-3)=5^(x-2) Find the exact solution, using common logarithms, and a two-decimal-place approximation of each solution, when appropriate. Answer: (log(8/25))/(log(4/5))=5.11 We had a sub today and he was terrible, we didn't have an example like this. Can someone help me?? :/ I keep trying it out and I just don't know what I am doing anymore. Please and thank you!
it is a lot of algebra after the first step
first step is \[(2x-3)\log(2)=(x-2)\log(5)\] then solve for \(x\) with the understanding that \(\log(2)\) and \(\log(5)\) are just some constants
multiply out first, get \[2\log(2)x-3\log(2)=\log(5)x-2\log(5)\] then put all terms with \(x\) on one side of the equal sign, everything else on the other
\[2\log(2)x-\log(5)x=3\log(2)-2\log(5)\]
factor out the \(x\) from the left hand side, get \[\left(2\log(2)-\log(5)\right)x=3\log(2)-2\log(5)\] then divide as the last step
\[x=\frac{3\log(2)-2\log(5)}{2\log(2)-\log(5)}\]
that is the answer, the rest is showing off, since \(3\log(2)=\log(2^3)=\log(8)\) and similarly \(2\log(5)=\log(25)\)
so the numerator is \(\log(\frac{8}{25})\) but all that is unnecessary nonsense, it doesn't help compute the number
that also explains why the denominator is \(\log(\frac{4}{5})\)
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