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Mathematics 28 Online
OpenStudy (anonymous):

the width of a rectangle is fixed at 6cm. Determine those lengths for which the area will be less than 126 square cm.

OpenStudy (campbell_st):

well if the length is 21 the area is 6 x 21 = 126 cm^2 so 21 is the upper limit of your measurements for length. You just need an inequality to represent it hope this helps

OpenStudy (mathstudent55):

The area of a rectangle is given by the formula A = LW where A = area, L = length and W = width We can solve the equation for L, A = LW LW = A We know W = 6 and we want the area to be less then 126, so we write L(6) < 126 L < 126/6 L < 21

OpenStudy (campbell_st):

so can the length be 21... that will help with the inequality

OpenStudy (anonymous):

Area of this rectangle is 6 multiplied by some length x. And 6x has to be less 126cm^2. We can put this in an inequality to solve for x: 6x < 126 x < 126/6 x < 21 But remember, since we are dealing with a length here, the length must be a positive number. Thus the possible values of length x are in the interval: 0 < x < 21

OpenStudy (anonymous):

oh ok 21 is the answer than i guess my answer was wrong.

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