Question

Hi! Good afternoon. I'm Maynard E. Javier student in SLSU. I have a project. Could anyone help me?

Can you explain to me the Area of Polar Coordinates?

Answer 1

Are you @khel ?

Answer 2

No.

Answer 3

Oh, sorry. khel asked me to help him/her with project, I assumed you are the same person.

Besides you can google it.
https://www.google.com/search?q=Area+of+Polar+Coordinates&aq=f&oq=Area+of+Polar+Coordinates&aqs=chrome.0.57&sourceid=chrome&ie=UTF-8

Answer 4

No, I'm not. But thank you anyway.

Answer 5

anong kurso mo maynard?

Answer 6

I am solving area of polar coordinates and I encounter a problem. I cannot understand why (1-cos2θ)dθ becomes [θ-1/2sin2θ] from the equation 〖(1+sinθ)〗^2 dθ. Can you please answer me. Thank you.

Answer 7

@dranyam , anong kurso mo?

Answer 8

BS Math po

Answer 9

ah, kaklase mo ung pauline par?

Answer 10

yes. why? do we have the same topic?

Answer 11

di po. points in space topic nya.

as to your question, \[\int (1-\cos2\theta) d\theta=\int 1 d\theta - \int \cos 2\theta d\theta\]

Answer 12

standard formula
\[\Large \int \cos ax dx = \frac{1}{a}\sin ax + C\]

Answer 13

nasagot na po ba?

Answer 14

yes. thank you very much. How about the intersection of the graph? I saw in a certain example that the interval of the equation r=2-sinΘ and r=3sinΘ is from Π/6 to Π/2. How should I know the interval? Is there any other formula?

Answer 15

can you be more specific with what is asked involving two polar equations?

Answer 16

How can I get the interval of that two equations?

Answer 17

solve the system of equations \[\large \begin{cases}r=2-\sin\theta\\r=3\sin\theta\end{cases}\]
here's the graph courtesy of Microsoft Mathematics
the two points of intersection are at \[(\frac{3}{2},\frac{\pi}{6}),\quad(\frac{3}{2},\frac{5\pi}{6})\], not at pi/2