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OpenStudy (anonymous):
At a given instant of time the position vector of a particle moving with a velocity 3i-4j+5k is i+9j-8k. Its angular velocity is ..
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OpenStudy (anonymous):
Angular velocity (omega) = V cross R
OpenStudy (anonymous):
I thought it is v = omega cross r. let me take the cue and solve it.. i j k 3 -4 5 1 9 -8 or w = -13i + 29j + 31 k Answer given as w = 13i -29j-31k/146..pl help
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