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Solve the equation of (¼)log6 (a – 3) – log6 3 = 0. A. 22 B. 64 C. 84 D. 96
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You need two rules for logarithms here:\[k \cdot \log_{a}b =\log_{a}b^k \]and\[\log_{a}b -\log_{a}c=\log_{a}\frac{ b }{ c } \]
\[\log_6 a - \log_6 b = \log_6 \left(\dfrac{a}{b}\right)\]So \(\log_6 \left(\dfrac{[a - 3]^{1/4}}{3}\right) =0\) is a start
ok
gotta notice that \(0\) can be written as \( \log_6 1\)
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