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Probability 12 Online
OpenStudy (anonymous):

Four cards are randomly chosen (without replacement) from a deck of 52 cards. Let K be the event that two of the four cards are King and the other two are Aces. Let E be the event that one of the four cards is a King of Hearts. The conditional probability P(K | E) is equal to

OpenStudy (anonymous):

without replacement, so it's a multivariate hypergeometric distribution, have you figured out the events yet?

OpenStudy (anonymous):

P(K)={2K,2A}and P(E)={K HEART}

OpenStudy (anonymous):

Exactly I guess it's like that: \[\Large P(K)=(2K,2A) \\ \Large P(E)=(K_{<3},XYZ) \] Where XYZ are random cards, I can only guess that by the problem given. as they don't state any restrictions on the remaining card. It only can't be another King.

OpenStudy (anonymous):

so how can i approach this qn?

OpenStudy (anonymous):

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