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If a normally distributed group of test scores have a mean of 70 and a standard deviation of 12, find the percentage of scores that will fall below 50. a. 4.75% b. 45.25% c. 6.75% d. 35.54%
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z = (50 - 70)/12 = -1.67. P(z<-1.67) = 0.04746. The percentage of scores below 50 (which is the same as the probability a score is less than 50) is 4.75%
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