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Pi form please! A regular hexagon with sides of 3" is inscribed in a circle. Find the area of a segment formed by a side of the hexagon and the circle. (Hint: remember Corollary 1--the area of an equilateral triangle is 1/4 s2 √3.)
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The hexagon is inscribed so the circle has a radius of 3" Area of the circle = pi*(3)^2 Find the area of the hexagon using your Corollary. Area of circle - area of hexagon = left over area. Left over area / 6 = segment formed by a side of the hexagon and the circle
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