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(4 to the -1 over 3)-2
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so\[\frac{ 4^{-1} }{ 3^{-2 }}\]
the rule of exponents is if it is a negative, it flips to the reciprocal. then 4^-1 goes to 1/4^1, numerators go to denominators and visaversa
\[\frac{ 4^{-1} }{ 3 }-2\] = \[\frac{ 1 }{ 4*3 }-2\]
4 to the -1 over three and in parentheses and all to the -2
yeah if that is what's asked then that is right.
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but the rule still applies
\[(\frac{ 4^{-1} }{ 3 })^{-2}\]=\[(\frac{ 1 }{ 4*3 })^{-2}\]=\[(\frac{ 1 }{ 12 })^{-2}\]=\[(\frac{ 12 }{ 1 })^{2}\]=144
fmadson, i would learn to type the equation in numbers how it is to look, it would help everyone involved
ok thanks
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