Question

I really need help solving this radical equation. Please help!

Answer 1

Where's the equation?

Answer 2

\[\sqrt{x+2} +4=x\]

Answer 3

I need a step by step. I keep getting it wrong. I could show you my steps if needed.

Answer 4

Yeah, if you can then please (: I need a little refresher. This is Algebra, right? Just checking that I'm qualified to answer, because I'm taking Algebra 2

Answer 5

yeah, algebra 2. hold on just a second.

Answer 6

Wait, it would take me a long time to write those out...

Answer 7

Alright, so, the step-by-step summary confused you? Just asking for reference. I have no problem working it out with you.

Answer 8

no, haha the problem confused me. It's just they didn't show any examples of this kind of problem in the lesson.

Answer 9

So you get it now? :D

Answer 10

no, I still need help..

Answer 11

√6(12)+9 + 2 = 11
First, we have to isolate the radical onto one side. By its lonesome.
Therefore, we must subtract the only number not in the radical (which is √6(12)+9 + 2) on both sides.

Answer 12

wait, no, not that problem. The first one i wrote.

Answer 13

√x+2 + 4= x
Same thing here, subtract 4 from both sides and get
√x+2 = x - 4

Answer 14

Then, raise each side of the equation to the same power - this way, you'll cancel out the radical because those are a pain.

Answer 15

i raised it to the second power, I got it so far

Answer 16

So it's now x + 2 = x^2 + 16

Answer 17

okay, I see it.

Answer 18

so, the answer it x=14?

Answer 19

Yep!

Answer 20

yay! So, now i just have to check my answer..

Answer 21

Yes, let's try it...