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Mathematics 19 Online
OpenStudy (anonymous):

Use the matrix inverse to solve the system of equations

OpenStudy (anonymous):

x + 5y = 3 2x 7y = 6:

OpenStudy (anonymous):

I don't understand how to do it because ad-bc=0???

OpenStudy (anonymous):

im doing similar stuff in my class right now but idk how to do this either lol

OpenStudy (anonymous):

\[\left[\begin{matrix}-1 & 5 \\ 2 & -7\end{matrix}\right] \left[\begin{matrix}x \\ y\end{matrix}\right]=\left[\begin{matrix}3 \\ 6\end{matrix}\right]\]

OpenStudy (anonymous):

then \[\left[\begin{matrix}-1 & 5 \\ 2 & -7\end{matrix}\right]^{-1}= \frac{ 1 }{ 0 }\left[\begin{matrix}-7 & -5 \\ -2 & -1\end{matrix}\right]\]

OpenStudy (anonymous):

Like what... am I doing this right

OpenStudy (abb0t):

\[A^{-1}=\frac{ 1 }{ detA }\ \left[\begin{matrix}d & -b \\ -c & a\end{matrix}\right]\]

OpenStudy (anonymous):

detA = 0?

OpenStudy (anonymous):

OMG LOL NVM

OpenStudy (anonymous):

I did 5+2 lol

OpenStudy (abb0t):

\[\frac{ 1 }{ ad-bc }\]

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

can one of you help me with my problem?... it has to do with matrices but it's simpler than this.

OpenStudy (anonymous):

I can try tag me to your question

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