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OpenStudy (anonymous):
Use the matrix inverse to solve the system of equations
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OpenStudy (anonymous):
x + 5y = 3
2x 7y = 6:
OpenStudy (anonymous):
I don't understand how to do it because ad-bc=0???
OpenStudy (anonymous):
im doing similar stuff in my class right now but idk how to do this either lol
OpenStudy (anonymous):
\[\left[\begin{matrix}-1 & 5 \\ 2 & -7\end{matrix}\right] \left[\begin{matrix}x \\ y\end{matrix}\right]=\left[\begin{matrix}3 \\ 6\end{matrix}\right]\]
OpenStudy (anonymous):
then \[\left[\begin{matrix}-1 & 5 \\ 2 & -7\end{matrix}\right]^{-1}= \frac{ 1 }{ 0 }\left[\begin{matrix}-7 & -5 \\ -2 & -1\end{matrix}\right]\]
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OpenStudy (anonymous):
Like what... am I doing this right
OpenStudy (abb0t):
\[A^{-1}=\frac{ 1 }{ detA }\ \left[\begin{matrix}d & -b \\ -c & a\end{matrix}\right]\]
OpenStudy (anonymous):
detA = 0?
OpenStudy (anonymous):
OMG LOL NVM
OpenStudy (anonymous):
I did 5+2 lol
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OpenStudy (abb0t):
\[\frac{ 1 }{ ad-bc }\]
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
can one of you help me with my problem?... it has to do with matrices but it's simpler than this.
OpenStudy (anonymous):
I can try tag me to your question
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