Solve the matrix equation AX = B for the 2 3 matrix X, given...
\[A= \left[\begin{matrix}4 & -1 \\ -1 & 0\end{matrix}\right] and B=\left[\begin{matrix}3 & 7 & -2 \\ 0 & -4 & -1\end{matrix}\right]\]
I don`t know how to do this
do I times each by the inverse of matrix A?
yes you need to find the inverse of matrix A first then you multiply both sides on the left by this inverse
so if C is the inverse of matrix A, then X = C*B
keep in mind that the order matters and C*B is NOT the same as B*C
so it should equal \[x= \left[\begin{matrix}0 & 4 & 1 \\ -3 & 9 & 6\end{matrix}\right]\]
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very nice KatClaire, you got it
Thank you :)!!
yw
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