write an equation of a line that passes through (-6,2) with slope 2/3
Use the point-slope form of an equation of a line: y-y1= m(x-x1)
wait how would i put them in here?
oh sry, i thought ur slope was a coordinate poitn...my bad sry
i get messed up with the y and x things
-6 is ur x 2 is ur y
so then i have 2-y^1=m(-6-x^1)
Slope-intercept form is like this: y = mx + b where m is the slope, and b is the y intercept. So they give you the slope of 2/3 which means m = 2/3, right? They also give you point (-6,2) which means they have given you an x-value and a y-value for this line: x = -6 and y = 2. Good so far?
im not sure this is the answers i have A)y=2/3x+8 B)y=2/3x+6 C)y=2/3x-2 D)y=2/3-4
what i'm asking, is if you understand what i've written so far:)
o yeah i understand
sorry got confushed
what are you confused on?
i dont know now
I'll start over then:) (This is really important to understand because it's the basics)
ok
So the choices you are given are all in slope intercept form. (y = mx + b) Right?
yes
Okay:) And you are given the slope = 2/3 and the point = (-6,2) right?
yes
and the equation y = mx + b is what we'll plug that info into okay? SO if m = the slope and b is the y intercept (the y part of the point they gave you) can you plug it in?
2=-6x+b? is this how i would plug them in?
um no. the only thing you're pluggin in is the slope where the m is and the y intercept where the b is :)
can you try again?
y=2/3x+-6?
wait. you are VERY close. You accidentally put the x- intercept in there instead of the y - intercept. Try once more :D
y=2/3x+2
YAY! There you go:D
okay:)
would the +2 turn to -2?
Only if the 2 was a negative.
o, i dont have this answer to choice from
hmm. that's odd. are you sure you wrote this part right "(-6,2)" ?
yeah
i have y=2/3x+8 y=2/3x+6 y=2/3x-2 y=2/3x-4
did you post the question right though?
yes
is the slope supposed to be 2/3?? or -2/3?
write an equation of a line that passes through (-6,2) with slope 2/3.
thats the question
okay then. we can try another equation. y-y1= m(x-x1) with this equation, you plug in the 2 for the y1, and the -6 for the x1. can you do that for me?
If you plug it in, it should look like this: y-2= m(x+6) then you plug the slope (2/3) in with the m, and get y-2= 2/3(x+6) from here, you solve. do you understand so far?
i thought the 6 would be -
yay! it would (i was just seeing if you really cared about understanding it) So it's y-2= 2/3(x-6) now if we further solve it we get y - 2 = 2/3x - 4 we add 2 to both sides and the 4 turns into a 2 and we get what?
y=2/3x+6?
no the answer is y=2/3x-2
yay:) there you go :D sorry about the confusion about the last one.
its ok :)
(you're welcome i guess then?)
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