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Mathematics 22 Online
OpenStudy (anonymous):

urgent HELP!

OpenStudy (anonymous):

evaluate each finite series for the specifiednumber of terms 80-40+20-...,n=8

jimthompson5910 (jim_thompson5910):

use the formula S = a*(1-r^n)/(1-r) where in this case a = 80 r = -0.5 n = 8

OpenStudy (anonymous):

oh ok! can u help with two more

OpenStudy (anonymous):

determine whether each infinite geometric series converges or diverges. if converges stat the sum 150+30+6+... -10-20-40-...

jimthompson5910 (jim_thompson5910):

can you identify the value of r for each?

OpenStudy (anonymous):

first one is 5

OpenStudy (anonymous):

other one is .5

OpenStudy (anonymous):

is that correct @jim_thompson5910

jimthompson5910 (jim_thompson5910):

150 ---> 30 means you divide by 5 or that you multiply by 1/5 = 0.2

jimthompson5910 (jim_thompson5910):

so the first r value is r = 0.2

jimthompson5910 (jim_thompson5910):

since |r| <1, we know it converges

OpenStudy (anonymous):

oh .. what about the other one

jimthompson5910 (jim_thompson5910):

to find the infinite sum, use this formula S = a/(1-r)

jimthompson5910 (jim_thompson5910):

in the first one, a = 150, r = 0.2

OpenStudy (anonymous):

Yeah i got that! what about the second one

jimthompson5910 (jim_thompson5910):

-10-20-40-... a = -10 r = 2 (since -20 divided by -10 = 2) because r > 1, this series diverges

jimthompson5910 (jim_thompson5910):

actually because |r| > 1, this series diverges

OpenStudy (anonymous):

oh...i think i undersand! thanks so much! have a good night!

jimthompson5910 (jim_thompson5910):

you're welcome

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