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What is the ∫1/x2+x+1 dx ?
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You completed the square perfectly fine. Now the integral looks like this: \(\large \int \frac{1}{(x+\frac{1}{2})^2+(\frac{\sqrt 3}{2})^2} dx\)
Why do you put 3/4 as the (3√2)^2 ? \[ \int\limits_{}^{} \frac{\frac{ 4 }{ 3 }\ 1 }{ (\frac{ 4 }{ 3 }((x+\frac{ 1 }{ 2 })^{2} +\frac34)} \] \[\frac{ 4 }{ 3 }\ \int\limits_{}^{} \frac{ 1 }{ (\frac{ 4 }{ 3 }(x+\frac{ 1 }{ 2 })^{2} +1)} \] And what is next ?
This 3/4 has been written as (sqrt(3/4))^2 because we know a formula which says... |dw:1362090928639:dw| Ofcourse with a constant :-)
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