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Find the derivative with respect to x of the given combination at the given value of x. problem attached
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I'm so confused on how to get this answer.
were you able to find derivative of \(\sqrt {g(x)}\) first >
Yeah, I got \[\sqrt{16}\]
then I used the d(√u)= u ' / 2 √u formula
so I thought u' = 1 and u = √16
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i get √16 = 4 * 2 = 8
but not sure where the 7 comes from :S
no, i meant derivative of \(\sqrt {g(x)}\) which will come in terms of x and not constant....
use chain rule...
you'll also have g'(x) in the numerator...
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\[d(\sqrt{g(x)})=\frac{1}{2\sqrt{g(x)}}g'(x)\]
yup...now x=3 will give u 7/8 right ?
because g'(3)=7
Yes. I didn't know I had to multiply by g'(x) .
now you know :) any doubts ?
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Nope. Thanks for the help :)
welcome ^_^
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