A point charge Q1=−2 μC is located at x=0, and a point charge Q2=+8 μC is placed at x=−0.5 m on the x-axis of a cartesian coordinate system.

Question

anonymous · Answer

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What is E(x) (in N/C) for x=-43.5 m
Just want a quick conformation of whether or not it's 29.428 N/C @Mashy

anonymous · Answer

this is the first homework right?? 

just check the answer.. duh!!

anonymous · Answer

i mean in that. you can click on CHECK ANSWER

anonymous · Answer

I says it's wrong :P
I've checked it a million times

yrelhan4 · Answer

whats the question?

anonymous · Answer

i remember getting the answer right :D

anonymous · Answer

dang it, mashy :P

anonymous · Answer

do the calculation man... it needs calci.. i dunno where my calci is..

anonymous · Answer

wait.. lemme login and see the answers

anonymous · Answer

haha 
and i only did the calculation for a couple thousand times so......

anonymous · Answer

my net is slow..!! it not loading :(

anonymous · Answer

wait wait.. wait arrr

anonymous · Answer

the numbers are not the same for everybody. they're randomly generated.

anonymous · Answer

oh is it.. cause i remember the same numbers for me too :P

anonymous · Answer

oh

anonymous · Answer

wait hold on laa!

anonymous · Answer

thats how TV TALKS :D hahaha

anonymous · Answer

bahahaaha

anonymous · Answer

ok the first one right??

anonymous · Answer

uh huh

anonymous · Answer

oh yea.. the main question is same.. but the number is differnt lol sorry :D

anonymous · Answer

lol toldja :P

anonymous · Answer

good luck :D.. you must be doing something wrong.. show your work here!

anonymous · Answer

$$\Large9 \times 10^{9} * 2 \times 10^{-6} (\frac{4}{43^{2}}-\frac{1}{43.5^{2}})$$
that gives me 29.428

anonymous · Answer

this is from edx ryt?

anonymous · Answer

yes

anonymous · Answer

yup