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x+2 is a binomial because it has two terms. It is also a polynomial.
Your question is confusing because the problems you have posted are division problems. The numerators are trinomials and the denominators are binomials
Could you please post the question EXACTLY as it is written?
If you divide and the remainder is 0 then the binomial is a factor of the polynomial.
Let's think about a numerical example. Is 4 a factor of 12?
How do you know?
Yes. It is a factor because 4 times 3 = 12. Is 5 a factor of 12? No. Because there is no integer that makes this true: 5(?) =12
So let's extend this to polynomials. (x+3)(x+2)= x^2+5x+6 So therefore (x^2+5x+6)/x+2= x+3 and (x^2+5x+6)/x+3=x+2
Yes. Or you don't have to do the division if you do the factoring.
I can say that 4 is a factor of 12 by showing that 4 x 3 = 12. I don't have to do the division.
Similarly I can say that x+2 is a factor of x^2+5x+6 by showing that (x+2)(x+3)=x^2+5x+6
Let's not get all tangled up in the terminology. x^2+5x+6 is a trinomial. It is the result of multiplying two binomials. The two binomials are x+2 and x+3
All of them are polynomials
I know you are. That's why I wanted you to state your problem exactly as written so I could help you understand it.
Are you talking about your original post?
\[5^2-10x^2+7x^2=25-3x^2\]
10x^2 is not a factor of that binomial so I guess I don't understand what you are saying.
Do you have another problem you could post?
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