Question

If f(x) = 4x, g(x) = 2x - 1, and h(x) = x^2 + 1, find each value.
35. f[g(-1)]
36. h[g(4)]
37. g[f(5)]

Answer 1

@genius12

Answer 2

Did you read my explanation on composite functions in your previous question? @Firejay5
If you haven't already, please do so. It will help you.

Answer 3

A. To find the f(g(-1)) take the function g and replace x with -1
B. Now take the function f and replace x with the answer you go in A

Answer 4

You are so good at this

Answer 5

Now, instead of plugging in whole functions, they are asking you to evaluate a function and then plug in the value.
So here is how it looks:

f[g(-1)] = f(-3) ---> This is because in order to find f[g(-1)], we must first find g(-1). When we do that, we can replace g(-1) with that value and find f[g(-1)]. To find g(-1), you plug in -1 in to g(x), i.e. g(-1) = 2(-1) - 1 = -3

Now that we know g(-1) = -3, we can replace g(-1) in f[g(-1)] with -3 so it becomes f(-3). Now since f(x) = 4x, and we want to find f(-3), we just plugin -3 wherever there is an x in the function to find the answer.

f(-3) = 4(-3) = -12

Now try the rest and see if you can do them.

Answer 6

so you did 35 for me correct

Answer 7

@genius12 I have a question

Answer 8

so if it starts with f[h(1)] then would it be the first equation f(x) = 4x