Anna applies a force of 19.5 newtons to push a book placed on a table. If the normal force of the book is 51.7 newtons, what is the coefficient of kinetic friction?

Question

shane_b · Answer

The normal force of the book (assuming a level table) is:$$F_{N}=mg$$Where g is the acceleration due to gravity (9.8m/s^2).

The formula you're looking for here is:$$F_k=\mu_kF_{N}$$Plugging in your values you end up with:$$19.5N=\mu_k(51.7N)$$All you need to do is solve for Uk

shane_b · Answer

So 19.5N/51.7N =?

anonymous · Answer

so i came up by dividing 0.377 then rounded up it will be 0.38
i was afraid to answer it and get the answer wrong so i came for a confirmation ^_^

shane_b · Answer

Good...and you have the right number of significant figures too so your answer is 100% correct.

shane_b · Answer

Time for sleep, good luck !

anonymous · Answer

thank you Night! :)