Question

Due to lack of SmartScore in Engagement, let me ask you a question. If possible, how do you solve for x algebraically? \[\Huge e^x = x^{\pi}\]

Answer 1

yes its posssible

Answer 2

How? I can't do it, lol.

Answer 3

you'll get an answer in log,
do you know logarithms ??
tale natural log on both sides....

Answer 4

x = πlnx

I still need to get x isolated.

Answer 5

yeah, i realized it now :P

Answer 6

Lol.

Answer 7

Yeah. I checked WolframAlpha and answers is very strange. I guess it isn't possible.

Answer 8

You said it is possible! @some_someone

Answer 9

Yes it is possible. You just have to find the right approach.

Answer 10

Can you show me how to do it?

Answer 11

@genius12 ?

Answer 12

Ya hold on lol.

Answer 13

I don't think there is any algebraic method for solving this. When wolfram gives it a funky name as they did in this case (The productlog function), then it usually won't have a solution using normal methods. XD

You can probably approximate the solution using some type of analytic method. But I dunno :)

Answer 14

Yeah, but we have to wait and see what @genius12 is going to say, lol.

Answer 15

;p

Answer 16

He holds the brain power of 12 geniuses! :O Surely he can crack this one!!

Answer 17

I sure hope he isn't trolling XD
http://weknowmemes.com/wp-content/uploads/2012/01/op-will-surely-deliver-lets-just-wait.jpg

Answer 18

Have you ever heard of this concept known as, solve by graphing? That's what you do when you can't find an algebraic method of doing it.

You simply graph the two functions and you get x = 1.74. There are algebraic ways of solving this, I'm just too lazy to do it, but if I work something out I'll tell you. Until now, let's stick to the graphing method lol.

Answer 19

The question was "how do you solve for x algebraically"...

Answer 20

I want to solve it algebraically :(

Apparently we have been tricked!

Answer 21

hehe

Answer 22

Shutup I'm solving it.

Answer 23

Sorry, take your time. I have seen enough to accept the fact that it isn't possible. If you figure it out, let me know.

Thank everyone for your time!