The functions f and g are given by f(x)=√x and g(x)=6-x. Let R be the region bounded by the x-axis and the graphs of f and g, as shown in the figure in the link below. Please show your work. h t t p://goo.gl/jXIZD
The functions f and g are given by f(x)=√x and g(x)=6-x. Let R be the region bounded by the x-axis and the graphs of f and g, as shown in the figure in the link below. Please show your work. h t t p://goo.gl/jXIZD 1. Find the area of R. 2. The region R is the base of a solid. For each y, where 0<=y<=2, the cross section of the solid taken perpendicular to the y-axis is a rectangle whose base lies in R and whose height is 2y. Write, but do not evaluate, an integral expression that gives the volume of the solid. 3. There is a point P on the graph of f at which the line tangent to the graph of f is perpendicular to the graph of g. Find the coordinates of point P.
Can you upload a picture, because I can't open the link
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Well, I will upload a picture
Painted area you need to find.
Firstly, you need to find x values, where these two graphis intersects. Do you know how to do it?
@Bladerunner1122
No, how do I do that?
And if possible it should be without the calculator.
Well, actually, you don't need to, because you have a pont (4;2) given. If you don't have any point, you need to solve this: √x=6-x
Well, it is easy, you won't need to use a caculator
Secondly, you need to find there g(x)=6-x intersects Ox line, do you know why you need to do it?
Wouldn't g(x)=6-6?
Since I have the point I don't need to solve for it right?
no, g(x) intererects Ox when 0=6-x x=6
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