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Algebra
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how do you factor this completely 4x^3 + 12x^2 + 3x + 9
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i think one of the factors is \(x+3\)
ya thats 1 but is the other 1 4x^2 or 12x^2 + 3
gimmick is to write it as \[x(4x^2+3)+3(4x^2+3)\]
\[(x+3)(4x^2+3)\]
thinks preciate it
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