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Algebra 12 Online
OpenStudy (anonymous):

how do you factor this completely 4x^3 + 12x^2 + 3x + 9

OpenStudy (anonymous):

i think one of the factors is \(x+3\)

OpenStudy (anonymous):

ya thats 1 but is the other 1 4x^2 or 12x^2 + 3

OpenStudy (anonymous):

gimmick is to write it as \[x(4x^2+3)+3(4x^2+3)\]

OpenStudy (anonymous):

\[(x+3)(4x^2+3)\]

OpenStudy (anonymous):

thinks preciate it

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