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Chemistry 15 Online
OpenStudy (anonymous):

How many moles of NaCl would be produced in the equation Na2CO3 + 2HCl --> 2NaCl + H2O + CO2

OpenStudy (anonymous):

? how did you figure that?

OpenStudy (abb0t):

There's a number 2 in front of NaCl..

OpenStudy (anonymous):

....its been a long day

OpenStudy (anonymous):

2 should not be the right answer....If you give me a sec I can work it out and explain it to you if you want... unless 2 is what you were looking for? .. That wouldn't be the answer my teacher wants tho

OpenStudy (anonymous):

same, thank you! if you could that would be lovely!

OpenStudy (anonymous):

well actually that might be what they're looking for.... I thought it gave you an amount in grams. to begin w/ in which case theres a formula to do .. but if it doesn't i'm not sure what else they would be looking for? .. are you doing something where it immediately tells you if your answer is right/wrong?

OpenStudy (anonymous):

it is for a lab write up..the first question was asking to calculate the moles of sodium carbonate that react. I got .0094 mol. The next question is asking to use the balanced equation to calculate the moles of NaCl that should be produced... all of these questions add up to finding the percent yield of sodium chloride

OpenStudy (anonymous):

okay so you have .0094 of Na2Co3 then?

OpenStudy (anonymous):

The answer should be 0.0188 mol of NaCl is produced. You have .0094 mol Na2CO3 And for every 1 mole of Na2CO3 you have you can produce 2 moles of NaCl. Soooo ... 0.0094 Mol Na2CO3 x 2 mol NaCl / 1 mol Na2CO3 ... Na2CO3 cancels out and leaves you with Moles of NaCl (0.0188) Hopefully this helps you

OpenStudy (anonymous):

thtnk you!

OpenStudy (anonymous):

Very welcome. Hope it's correct!!

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