Question

Please help me solve 0 < (2x-4)^-1< 1/2

Answer 1

\[0< \frac{ 1 }{ 2 x-4 }<\frac{ 1 }{ 2 }\]
\[x>3\]

Answer 2

oh? wow that is a great website? yeah does it include step by step though?

Answer 3

yes. but it just gives solution, does not tutor...

Answer 4

oh :(

Answer 5

How did you get from step 1 to step 2 :S

Answer 6

are you still having problems ? or is this solved ?

Answer 7

I mean I cant understand how he got from step 1 to step 2 ( first poster)

Answer 8

if a/b < c/d
then b/a > d/c
so, when 1/ (2x-4) < 1/2
then , 2x-4 > 2

Answer 9

Got it now! thanks!

Answer 10

goku saved the day !

Answer 11

:P

Answer 12

:)

Answer 13

One last question am I able to remove the 0 < part because it is zero?

Answer 14

no, since we got x>3
means 'x' is positive, now if we multiply 2x-4 on all side, we get , 0< 1
which is obviously true, but will not give us any inequality in x
so, only inequality we have is x>3

Answer 15

x>3 <--- kinda looks like a chicken/turkey squinting his/her eyes

Answer 16

then what does the inequality i <3u look like ? :P

Answer 17

So this is what I get to if I try to solve it by my own


0 < 1/(2x-4)^-1<1/2

0<1/2x-4<1/2

0<2x-4<2

-4<2x<-2


-2<x<-1


Where is my mistake?

Answer 18

im flattered LOL jk

Answer 19

third line cristo !!

Answer 20

flip the sign!

Answer 21

2nd line was mistyped it should be 0 < 1/2x-4<1/2

Answer 22

hmm sec

Answer 23

(2x-4)*0 =0
(2x-4)*1/2x-4 =1
and
(2x-4)*1/2 =x-2

Answer 24

On which line do I need to flip the sign ? :D

Answer 25

and why? :D

Answer 26

because of this :
if a/b < c/d
then b/a > d/c

so, 1/(2x-4) < 1/2
gives you
2x-4 > 2

Answer 27

don't consider both inequalities together, treat 0 < 1/(2x-4) and 1/(2x-4) < 1/2
separately.

Answer 28

I solved it! Thank you all!!!!!!!!

Answer 29

welcome :)