Let f(x) be the function 8x^2-3x+11 . Then the quotient f(2+h) - f(2)/h can be simplified to ah+b for: a= b=
what u got as f(2+h) =.. ?
nothing because I'm not exactly sure with derivatives.
to get f(2+h) from f(x), just replace 'x' in f(x) by '2+h'
8(2+h)^2-3(2+h)+11
Yeah, this is just algebra, that it happens to be the derivative is interesting but inconsequential for working the problem. You need to take what @hartnn gave you in the last post, subtract f(2), divide the whole enchilada by h and simplify. Then you can read out the values of a and b.
whats f(2)?
The value of the polynomial at x = 2: \[8(2)^3-3(2)+11\]
then what
??
then what u got as f(2+h) - f(2) =.. ?
32+32h+8h^2-6-3h+11-32-6+11/h
Pet peeve of mine: that's really (32+32h+8h^2-6-3h+11-32-6+11)/h Okay, so simplify that sucker! Collect like terms, cancel out any common factors between numerator and denominator...
i did. 32+8h-3
Okay, you can do a little more, I think...
Then go take another look at the problem statement. An important skill is recognizing when you've finished the problem, or what you have left to do...
they're asking what a and b
What's your final, completely simplified version of the result?
32+8h-3
No. You're not done yet.
idk
let me rearrange it: 32 - 3 + 8h
don't you have two terms you can combine to further simplify that?
aw yes!
thanks!
look out forehead, incoming palm! :-)
now can you find a and b?
8 and 29
there you go!
thanks =]
you bet. time for this guy to hit the sack. good night!
night!
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