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OpenStudy (shubhamsrg):
Time pass ques:
Use 5 zeroes with any mathematical functions to arrive at 14.
PS: This has a lame solution. -_-
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OpenStudy (anonymous):
f(x) = x - 100000
f(10014) = 14
OpenStudy (shubhamsrg):
cool.. B|
OpenStudy (shubhamsrg):
But NO :|
Parth (parthkohli):
Let \(f(n) = n + 14\). Then \(f(0 + 0 + 0 + 0 + 0) = 14\)
Parth (parthkohli):
B-)
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Parth (parthkohli):
My solution is lamer!
OpenStudy (shubhamsrg):
-_-
OpenStudy (mathstudent55):
f(x) = 1400000x
f(0.00001) = 14
I used 5 zeros twice :-)
OpenStudy (shubhamsrg):
good for you :)
OpenStudy (anonymous):
S(S(S(S(S(S(S(S(S(S(S(S(S(S(0+0+0+0+0))))))))))))))
This one is the lamest :D
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OpenStudy (shubhamsrg):
what is this anyways ?
OpenStudy (anonymous):
or \(p_{0!}p_{0!+0!+0!+0!}\), where \(p_n\) denotes the nth prime?
OpenStudy (anonymous):
S(n) = n + 1, succesor function
OpenStudy (shubhamsrg):
aha..hmm
I won;t say thats more lame, I'd say thats equally lame relative to my soln.! -_-
OpenStudy (shubhamsrg):
but still, its cool.. B|
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OpenStudy (anonymous):
What's your solution? :p
OpenStudy (shubhamsrg):
I'll message you.
Parth (parthkohli):
So the answer is...\[\left\lfloor \tan\left(\dfrac{0! + 0! + 0!}{0! + 0!}\right)\right\rfloor\]
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