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if the diameter of a spere is doubled what will happen to the volume of the sphere
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Volume of a sphere:\[V=\frac{ 4 }{ 3 }\pi r^3\] Now imagine your new sphere: it has 2r as radius ( double the diameter is double the radius), so it's volume will be:\[V_2=\frac{ 4 }{ 3 }\pi (2r)^3 \]Almost everything is just the same ... apart from the (2r)³. What will happen if you work out the brackets?
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