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Can someone help me find the domain for f(x) = x / sqrt(x-3) ?
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Well, can you take square root of negative numbers?
x=3
and no you cant
You didn't answer my question. Are you allowed to take square root of negative numbers?
Right. Are you allowed to divide by zero?
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No
You've got 2 problems here: 1. sqrt(x-3) may not be 0, because you can't divide by 0. 2. x-3 >= 0 otherwise, you can't take the sqrt...
ok, so then all you have to do is solve the inequality x-3 > 0
\[{x-3}> 0 \quad \therefore x>3 \]
thanks
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