Question

I need help with part 3.. Please help<3
Consider the line that passes through the point (-3, 2) and has a slope of 3.

Part 1: Write the equation of this line using point-slope form. (2 points)
Part 2: Using your equation from part 1, rewrite this equation in slope-intercept form. Make sure to show all of your work. (2 points)
Part 3: Using your equation from part 2, rewrite this equation in standard form. Make sure to show all of your work. (2 points)

Answer 1

Part 1: Plug into point slope formula: y-y1=m(x-x1)

Part 2: Solve for y

Part 3: Rearrange to standard form

Answer 2

y - 2 = 3(x - -3)
y = MX + B
y = 3x + 2

Thats what I have so far.

Answer 3

Thats correct. Great Job.

Answer 4

But how do I go back to standard?

Answer 5

The number with the x is the slope and the other number is the y-intercept.

Answer 6

Im still confused.

Answer 7

Part 3
4) use the slope and y-intercept of the above equation (part 2)
5) the standard from would look like y-a=x+b

Answer 8

Standard form for a line is \[Ax + By = C\] where \(A, B, C\) are integers and \(A\gt0\).

Answer 9

your standard form would be -3x+y = 2

Answer 10

@kayy15 Most texts I've seen have the condition that A > 0, in which case you would want to multiply that equation by -1 to change the signs.