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Find the derivative of f(x) = x|x| How to solve this?
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If x is negative, then what happens? If x is positive then what happens? Take the derivative of each case.
Can you do that?
Basically, \[ (x|x|)' = \left(\begin{cases} x^2 & x>0\\-x^2 & x<0\end{cases}\right)'=\begin{cases} 2x & x>0\\-2x & x<0\end{cases} = 2|x| \]
Fortunately the function is differentiable at \(0\) which sometimes isn't the case when you have absolute values in a function.
very detailed, thank you so much ^^
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