Question

Find the exact value of the composition.

arccos[sin(pi/6)]

Answer 1

sin\[\sin(\frac{\pi}{6}) = \frac{1}{2}\]

so you are finding

\[\arccos(\frac{1}{2})\]

which should be reasonably easy/

Answer 2

is it pi/3??

Answer 3

it is

Answer 4

\[
\arccos[\sin(\pi/6)]=\arccos[\cos(\pi/2-\pi/6)]=\pi/2-\pi/6
\]

Answer 5

thankyou guys!

Answer 6

They want you to use the co-function identity here: \[
\sin(x) = \cos(\pi/2-x)\\
\cos(x) = \sin(\pi/2-x)
\]